# Formatting Sandbox

Basically same as Formatting Sandbox in meta.SO, but since this and Statistical Analysis are the only 2 sites (I know) supporting TeX formatting, I believe we also need one here for testing it.

-
Theoretical computer science also supports $\mathrm{\TeX/\LaTeX}$ formatting. –  JeffE Jun 1 '12 at 7:29
@JeffE: You can use $\TeX$ and $\LaTeX$ (\Tex and \LaTeX) for the text. –  Asaf Karagila Jun 2 '12 at 21:09
@JeffE: In 2010 only 'stats' and 'math' support TeX formatting. Of course now there is also 'cstheory', 'cs', 'chemistry', 'quant', etc. –  KennyTM Jun 3 '12 at 6:25
test \begin{align*}\text{middle line}\end{align*} new line –  Ruslan Jan 30 at 13:06
test test $\not\in(1)\notin(2)$ Who's better??? –  user93957 Jan 31 at 22:25
$m^n + m^x + m^n = 555555$ test test –  hichris123 Feb 2 at 19:09

A suggestion: if you want to see you TeX previewed, pretend to type your question/answer. Then wait for 4 seconds. We have on the fly previewing for LaTeX here. This way we don't keep popping this question to the top of meta.

-
May be this (and the main sandbox) should be made special unbumpable question? –  Vi0 Aug 24 '12 at 15:06

This is a 1e1ea2ce-0342-4835-a7cc-ee70fbdfe27d
bug

-

$\hskip -3em \color{red}{\Rule{5em}{1em}{1em}}$. Testing of negative skips to overlap the buttons on the left.

$\rlap{\smash{\lower 3em{\color{red}{\Rule{5em}{2em}{0em}}}}}$Testing overlapping on the bottom. OK, both seem to be problems.

-
a comment with overlaps $\rlap{\color{red}{\Rule{10em}{1em}{0.5em}}}$ –  Davide Cervone Jun 14 '12 at 21:56
The extension linked to this answer can be used to improve the situation. –  Davide Cervone Jun 14 '12 at 22:00
$\rlap{\color{grey}{\Rule{200em}{1em}{0.75em}}}$ –  user93957 Jan 7 at 13:01

Testing spoiler:

Without newlines:

$$\lim_{x \rightarrow \infty} \dfrac{\ln(x^2+4)}{\ln(x+\sqrt{1+x^2})} = \lim_{x \rightarrow \infty} \dfrac{\ln(x^2) + \ln(1+4/x^2)}{\ln(x) + \ln(1+\sqrt{1+1/x^2})}$$ $$= \lim_{x \rightarrow \infty} \dfrac{\ln(x^2)}{\ln(x)} \dfrac{\left(1+\dfrac{\ln(1+4/x^2)}{\ln(x^2)} \right)}{\left(1 + \dfrac{\ln(1+\sqrt{1+1/x^2})}{\ln(x)} \right)}$$ $$= \lim_{x \rightarrow \infty} 2 \dfrac{\ln(x)}{\ln(x)} \lim_{x \rightarrow \infty} \dfrac{\left(1+\dfrac{\ln(1+4/x^2)}{\ln(x^2)} \right)}{\left(1 + \dfrac{\ln(1+\sqrt{1+1/x^2})}{\ln(x)} \right)}$$ $$= 2 \lim_{x \rightarrow \infty} \dfrac{\left(1+\dfrac{\ln(1+4/x^2)}{\ln(x^2)} \right)}{\left(1 + \dfrac{\ln(1+\sqrt{1+1/x^2})}{\ln(x)} \right)} =2$$

With newlines:

! $$\lim_{x \rightarrow \infty} \dfrac{\ln(x^2+4)}{\ln(x+\sqrt{1+x^2})} = \lim_{x \rightarrow \infty} \dfrac{\ln(x^2) + \ln(1+4/x^2)}{\ln(x) + \ln(1+\sqrt{1+1/x^2})}\\ = \lim_{x \rightarrow \infty} \dfrac{\ln(x^2)}{\ln(x)} \dfrac{\left(1+\dfrac{\ln(1+4/x^2)}{\ln(x^2)} \right)}{\left(1 + \dfrac{\ln(1+\sqrt{1+1/x^2})}{\ln(x)} \right)}\\ = \lim_{x \rightarrow \infty} 2 \dfrac{\ln(x)}{\ln(x)} \lim_{x \rightarrow \infty} \dfrac{\left(1+\dfrac{\ln(1+4/x^2)}{\ln(x^2)} \right)}{\left(1 + \dfrac{\ln(1+\sqrt{1+1/x^2})}{\ln(x)} \right)}\\ = 2 \lim_{x \rightarrow \infty} \dfrac{\left(1+\dfrac{\ln(1+4/x^2)}{\ln(x^2)} \right)}{\left(1 + \dfrac{\ln(1+\sqrt{1+1/x^2})}{\ln(x)} \right)} =2$$

-
I was trying this here because of the problems the poster had with this answer. –  Martin Sleziak Jun 1 '12 at 9:51


$$\newcommand{\sin}{FOO} \sin x$$

$$\sin y$$

$$\renewcommand{\nonexistent}{QUX} \nonexistent$$

-

And now what does it look like to another user who doesn't suspect that the command has been redefined?

$$\sin x$$

Very interesting.

-
Oh wow - that is interesting. How does one clear newcommands? –  mixedmath Jun 1 '12 at 7:07
@mixedmath: See meta.math.stackexchange.com/questions/4130/… –  Nate Eldredge Jun 1 '12 at 13:17

you may also go to MathURL and write your formula there; just remember the dollar signs before putting it here.

-

Let me try if there is a difference between single dollar signs $\sum_{i = 0}^n k^i$ and double dollar signs $$\sum_{i = 0}^n k^i$$

-
You can always use this: $\sum\limits_{i = 0}^n k^i$ –  Quixotic Sep 19 '11 at 20:12

$\rm{\bf Hint}\:\ (p\!-\!1)^2\! \mid p^q\!-1 \!\iff\! p\!-\!1\ \bigg|\ \dfrac{p^q\!-1}{p\!-\!1} = p^{q-1}\! +\cdots\!+p\! +\! 1$ $\rm\equiv q\ (mod\ p\!-\!1)$

-
\rm ${}{}{}{}{}$ –  user93957 Jan 7 at 13:00

$\def\col#1{\color{#1}{\text{#1}}}\col{white}$

I am testing whether there are any uses of the #rrggbb color notation to represent usefully distinguishable colors. Certainly $\col{#d10000}$ is distinguishable from $\col{#df0000}$, but the former is indistinguishable from $\col{#d00}$ and the latter from $\col{#e00}$.

## Red

$$\col{#000}\col{#080000}\col{#100}\\ \col{#100}\col{#190000}\col{#200}\\ \col{#200}\col{#2a0000}\col{#300}\\ \col{#300}\col{#3b0000}\col{#400}\\ \col{#400}\col{#4c0000}\col{#500}\\ \col{#500}\col{#5d0000}\col{#600}\\ \col{#600}\col{#6e0000}\col{#700}\\ \col{#700}\col{#7f0000}\col{#800}\\ \col{#800}\col{#900000}\col{#900}\\ \col{#900}\col{#a10000}\col{#a00}\\ \col{#a00}\col{#b20000}\col{#b00}\\ \col{#b00}\col{#c30000}\col{#c00}\\ \col{#c00}\col{#d40000}\col{#d00}\\ \col{#d00}\col{#e50000}\col{#e00}\\ \col{#e00}\col{#f60000}\col{#f00}\\$$

## Yellow

$$\col{#000}\col{#080800}\col{#110}\\ \col{#110}\col{#191900}\col{#220}\\ \col{#220}\col{#2a2a00}\col{#330}\\ \col{#330}\col{#3b3b00}\col{#440}\\ \col{#440}\col{#4c4c00}\col{#550}\\ \col{#550}\col{#5d5d00}\col{#660}\\ \col{#660}\col{#6e6e00}\col{#770}\\ \col{#770}\col{#7f7f00}\col{#880}\\ \col{#880}\col{#909000}\col{#990}\\ \col{#990}\col{#a1a100}\col{#aa0}\\ \col{#aa0}\col{#b2b200}\col{#bb0}\\ \col{#bb0}\col{#c3c300}\col{#cc0}\\ \col{#cc0}\col{#d4d400}\col{#dd0}\\ \col{#dd0}\col{#e5e500}\col{#ee0}\\ \col{#ee0}\col{#f6f600}\col{#ff0}\\$$

## Green

$$\col{#000}\col{#000800}\col{#010}\\ \col{#010}\col{#001900}\col{#020}\\ \col{#020}\col{#002a00}\col{#030}\\ \col{#030}\col{#003b00}\col{#040}\\ \col{#040}\col{#004c00}\col{#050}\\ \col{#050}\col{#005d00}\col{#060}\\ \col{#060}\col{#006e00}\col{#070}\\ \col{#070}\col{#007f00}\col{#080}\\ \col{#080}\col{#009000}\col{#090}\\ \col{#090}\col{#00a100}\col{#0a0}\\ \col{#0a0}\col{#00b200}\col{#0b0}\\ \col{#0b0}\col{#00c300}\col{#0c0}\\ \col{#0c0}\col{#00d400}\col{#0d0}\\ \col{#0d0}\col{#00e500}\col{#0e0}\\ \col{#0e0}\col{#00f600}\col{#0f0}\\$$

## Blue

$$\col{#000}\col{#000008}\col{#001}\\ \col{#001}\col{#000019}\col{#002}\\ \col{#002}\col{#00002a}\col{#003}\\ \col{#003}\col{#00003b}\col{#004}\\ \col{#004}\col{#00004c}\col{#005}\\ \col{#005}\col{#00005d}\col{#006}\\ \col{#006}\col{#00006e}\col{#007}\\ \col{#007}\col{#00007f}\col{#008}\\ \col{#008}\col{#000090}\col{#009}\\ \col{#009}\col{#0000a1}\col{#00a}\\ \col{#00a}\col{#0000b2}\col{#00b}\\ \col{#00b}\col{#0000c3}\col{#00c}\\ \col{#00c}\col{#0000d4}\col{#00d}\\ \col{#00d}\col{#0000e5}\col{#00e}\\ \col{#00e}\col{#0000f6}\col{#00f}\\$$

## Gray

$$\col{#000}\col{#080808}\col{#111}\\ \col{#111}\col{#191919}\col{#222}\\ \col{#222}\col{#2a2a2a}\col{#333}\\ \col{#333}\col{#3b3b3b}\col{#444}\\ \col{#444}\col{#4c4c4c}\col{#555}\\ \col{#555}\col{#5d5d5d}\col{#666}\\ \col{#666}\col{#6e6e6e}\col{#777}\\ \col{#777}\col{#7f7f7f}\col{#888}\\ \col{#888}\col{#909090}\col{#999}\\ \col{#999}\col{#a1a1a1}\col{#aaa}\\ \col{#aaa}\col{#b2b2b2}\col{#bbb}\\ \col{#bbb}\col{#c3c3c3}\col{#ccc}\\ \col{#ccc}\col{#d4d4d4}\col{#ddd}\\ \col{#ddd}\col{#e5e5e5}\col{#eee}\\ \col{#eee}\col{#f6f6f6}\col{#fff}\\$$

Conclusion: on a typical LCD monitor, a half-step (#08) is perceptible in the lighter colors, but not in the darker ones. Even a full step (#11) is too small to be useful for distinguishing different text in a post on this web site.

-
Note that whether or not those colors are distinguishable depends upon the capabilities of the monitor and graphics system. Most consumer level displays have limited capabilities (8-bit,low gamut). For some discussion see e.g. here. –  Bill Dubuque Jan 16 at 1:47
#00e means #0000ee not #0000e0. –  KennyTM Jan 16 at 8:12
@KennyTM Thanks! Of course it must be so, or else #FFF wouldn't be white. Thanks for pointing this out. –  MJD Jan 16 at 14:13
@Bill That is interesting, but not relevant to the issue of mathematical typesetting on this web site. –  MJD Jan 16 at 15:32
@MJD Sure it is. You are attempting to judge if color differences are perceptible on MSE. My point is that it is very difficult to accurately judge that unless one has professional-level graphics hardware and specialized knowledge in this area. For example, what you see as different may display the same to someone else using a monitor with less capability (e.g. one using dithering/interpolation from 8bit to 10bit color). –  Bill Dubuque Jan 16 at 15:48
I am trying to judge if color differences are usefully different. For example, you are fond of using colored text to highlight parts of equations, as here. The fact that $\color{#0000c3}{\text{#0000c3}}$ might be distinguishable from $\color{#0000cc}{\text{#0000cc}}$ on a professional-quality wide-gamut monitor is of absolutely no use to you in doing that. –  MJD Jan 16 at 15:52
My goal in writing this post was to decide if I should mention the #rrggbb notation in this post about typesetting colors, in addition to the #rgb notation. My conclusion is that there is no need to do that. –  MJD Jan 16 at 15:55
$\rlap{\color{#000}{\Rule{200em}{1em}{0.75em}}}\\ \rlap{\color{#010}{\Rule{200em}{1em}{0.75em}}}\\ \rlap{\color{#020}{\Rule{200em}{1em}{0.75em}}}\\ \rlap{\color{#030}{\Rule{200em}{1em}{0.75em}}}\\ \rlap{\color{#040}{\Rule{200em}{1em}{0.75em}}}\\ \rlap{\color{#050}{\Rule{200em}{1em}{0.75em}}}\\ \rlap{\color{#060}{\Rule{200em}{1em}{0.75em}}}\\ \rlap{\color{#070}{\Rule{200em}{1em}{0.75em}}}\\ \rlap{\color{#080}{\Rule{200em}{1em}{0.75em}}}\\ \rlap{\color{#090}{\Rule{200em}{1em}{0.75em}}}\\ \rlap{\color{#0a0}{\Rule{200em}{1em}{0.75em}}}\\ \rlap{\color{#0b0}{\Rule{200em}{1em}{0.75em}}}\\$ –  user93957 Jan 31 at 22:29

Can we do pictures?

\begin{picture}(2,2) \put(0,0){\line(1,0){1}} \put(0,0){\line(0,1){1}} \end{picture}

\begin{math} 2 \end{math}

aw dang..

-
See here –  t.b. Sep 18 '11 at 22:10
@TheoBuehler: Aw, dang. Thanks for the link. –  Mehrdad Sep 18 '11 at 22:28

$(\not \in \notin) 1 \times 2 \in S \implies S \notin S$

$$\lim_ {k\to\infty}^{\diamond \circ \square \sum \int} \sum_{j=1}^k {j^{2^j_k}_3}_{x_i} \int_2^3x\ dx$$

$C3^\#_\flat\natural\colon$ musical stuff!

$$&iexcl;^IGNORE\ \ M_e!$$

$$¡^IGNORE\ \ M_e!$$

$$!^IGNORE\ \ M_e!$$

$$\unicode{xA1}^IGNORE\ \ M_e!$$

-
Hm... odd... &iexcl;^IGNORE\ \ M_e! works in the preview. –  minitech Dec 3 '11 at 6:31
Okay, only one of three variants work... –  Ｊ. Ｍ. Dec 3 '11 at 6:53
Make that two.${}$ –  Ｊ. Ｍ. Dec 6 '11 at 14:23
Test: $\mathbb{R}^{n+1}$ –  Dan Moore Jul 12 '12 at 15:27

Can we enter nested math inside \text now, and have it saved? $$\{\,p\mid\text{p and p+2 are prime}\,\}$$ Edit: it seems we can.

-
But will Markdown respect it? $\text{This should not become a hyperlink:$test$}$ –  celtschk Jul 14 '12 at 10:28
The changes don't affect comments, only questions and answers. Comments seem to be processed quite differently. –  Davide Cervone Jul 14 '12 at 13:57
That's interesting. So $\text{does this$x^2$also not work properly?}$ Well, it seems to work. –  celtschk Jul 14 '12 at 16:06
MathJax properly handles nested dollars, but they are not protected from MarkDown when used in comments. They are when used in questions and answers. –  Davide Cervone Jul 14 '12 at 18:30

The preview recognizes $\rm\LaTeX$ environments and protects the contents from Markdown. Does that work once saved?

$$x _1 = y_ 1$$

Edit: It seems that it does!

-

Testing striking out:

math: text $a^2-b^2=(a-b)(a+b)$ text

tag: text text

url: text math.SE text

-
What about comments? math: <s> text $a^2-b^2=(a-b)(a+b)$ text </s> tag: <s> text tex text </s> url: <s> text math.SE text </s> –  Martin Sleziak Jun 20 '12 at 12:53
Any concave function $f\colon0,\infty)\to\mathbb R$ such that $f(0)=0$ is [subadditive. –  Martin Sleziak Jun 28 '12 at 14:10
Any concave function $f\colon[0,\infty]\to\mathbb R$ such that $f(0)=0$ is subadditive. –  Martin Sleziak Jun 28 '12 at 14:12
What about \left[\right)? Any concave function $f\colon\left0,\infty\right)\to\mathbb R$ such that $f(0)=0$ is [subadditive. –  Martin Sleziak Jun 28 '12 at 14:33
$\left[0,\infty\right)$ and [link](http://math.stackexchange.com)` produces $\left0,\infty\right)$ and [link. –  Martin Sleziak Jun 28 '12 at 14:43

-
$$\require{cancel}\cancelto{1}{\dfrac{\sqrt{7x^7-y^9}}{8x^3+1}}$$